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-16x^2+28x+210=0
a = -16; b = 28; c = +210;
Δ = b2-4ac
Δ = 282-4·(-16)·210
Δ = 14224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14224}=\sqrt{16*889}=\sqrt{16}*\sqrt{889}=4\sqrt{889}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{889}}{2*-16}=\frac{-28-4\sqrt{889}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{889}}{2*-16}=\frac{-28+4\sqrt{889}}{-32} $
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